Joy Oyebisi Tutoring

Joy Oyebisi Tutoring Helping students excel in chemistry and build confidence through personalized tutoring, small group classes, and engaging content.

09/30/2026

Ka vs. pKa: How do you know which acid is stronger?

Understanding Ka and pKa makes comparing acid strength much easier!

Higher Ka = stronger acid
Lower pKa = stronger acid

Why? A stronger acid dissociates more in water, so it has a larger Ka value. Since pKa = −log(Ka), the relationship is reversed for pKa.

Quick rule to remember:
Ka ↑ → Acid strength ↑
pKa ↓ → Acid strength ↑

Save this reel for your next chemistry study session!

09/22/2026

Chemistry tip!

Converting meters to centimeters doesn't have to be complicated!

Using dimensional analysis, you can convert units step by step and make sure your units cancel correctly.

Remember: 1 m = 100 cm

Save this for your next chemistry class!

Need help with Chemistry? I'm here to help!

Looking for chemistry support this school year? I offer both small-group and 1-on-1 chemistry support to help students b...
09/15/2026

Looking for chemistry support this school year?

I offer both small-group and 1-on-1 chemistry support to help students build strong foundations, understand challenging concepts, keep up with coursework, and prepare for exams.

- High School Chemistry
- AP Chemistry
- College/University Chemistry

Whether your student learns best in a small group or needs more personalized attention, there’s an option to fit their needs.

📩 Message me to learn more or get started.

🎒📚 BACK TO SCHOOL = TIME TO GET ACADEMIC SUPPORT IN PLACE!Is your child taking Chemistry, Math, Physics or Biology this ...
09/04/2026

🎒📚 BACK TO SCHOOL = TIME TO GET ACADEMIC SUPPORT IN PLACE!

Is your child taking Chemistry, Math, Physics or Biology this year?

If they struggled last year, are entering a more challenging grade, or simply need extra support to stay confident and on track, I can help! 💜

I’m Joy Oyebisi, PhD, a STEM tutor with 5+ years of tutoring experience.

Chemistry | High School | AP/IB | University-level | 1-on-1 & Small Group Sessions

📩 DM me to learn more or book a consultation @ www.joyoyebisitutoring.com

Give your child the support they need to start the school year strong!

09/03/2026

Summer Chemistry Challenge #10 Solution!

The correct answer is C. 10.0 g ✅

With a half-life of 8 hours, 24 hours represents 3 half-lives:

80 g → 40 g → 20 g → 10 g

And that's a wrap on our Summer Chemistry Challenge!

Thank you to everyone who participated throughout the series! 💜

Which challenge was your favourite? Let me know below!

Summer Chemistry Challenge #10 is here! And this one is a little special because it’s our LAST Summer Chemistry Challen...
09/01/2026

Summer Chemistry Challenge #10 is here!

And this one is a little special because it’s our LAST Summer Chemistry Challenge! 💜

Let’s finish the series with some Nuclear Chemistry!

Can you figure it out? Think about how many half-lives have passed before choosing your answer.

Drop your answer (A, B, C, or D) in the comments!

The solution will be revealed in 2 days.

Thank you to everyone who has participated in the Summer Chemistry Challenge series! Let’s make the final one count!

Celebrating Student Success! There are few things more rewarding as a tutor than receiving messages that remind you why ...
08/28/2026

Celebrating Student Success!

There are few things more rewarding as a tutor than receiving messages that remind you why you love what you do.

Recently, I received two messages that made me incredibly proud:

One student earned a 5 on her AP Chemistry exam! 🎉

Another student will be joining McMaster Health Sciences this fall! 🩺

Behind every achievement is hard work, persistence, consistency, and a student who kept going even when things got challenging.

I’m so proud of my students and grateful to have played a small part in their academic journeys. ❤️

To every student preparing for the new school year: keep showing up, keep asking questions, and keep believing in yourself.

Your hard work matters, and your goals are worth pursuing.

Here’s to celebrating more student successes! 🎉

08/27/2026

Summer Chemistry Challenge #9 – Solution!

The correct answer is C. Rate = k[A][B]²

When [A] doubles while [B] stays constant, the rate doubles → the reaction is first order in A.

When [B] doubles while [A] stays constant, the rate quadruples → the reaction is second order in B.

Therefore: Rate = k[A][B]²

Did you get it right? Let me know in the comments!

Keep following for the next Summer Chemistry Challenge!

Summer Chemistry Challenge #9 is here!This week, we're putting your rate law skills to the test!For the reaction A + B ...
08/25/2026

Summer Chemistry Challenge #9 is here!

This week, we're putting your rate law skills to the test!

For the reaction A + B → Products, use the experimental data to determine the correct rate law.

Don't just look at the options, compare the experiments carefully and see how changing the concentration of each reactant affects the reaction rate.

What’s your answer: A, B, C, or D? Drop it in the comments below!

The solution will be revealed in 2 days.

Challenge a friend and see who can crack the rate law!

08/20/2026

Summer Chemistry Challenge 8 – Solution!

The correct answer is B. The reaction is exothermic and ΔH = −150 kJ.

When a reaction releases heat to the surroundings, it is exothermic. Because energy leaves the system, the enthalpy change, ΔH, is negative.

Exothermic = heat released = negative ΔH

Did you get this one right? Let me know in the comments!

Stay tuned for Summer Chemistry Challenge No. 9 next week!

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