21/06/2022
πFood for thought for Grade 12's. Application of calculus proves that any parabolic function f(x) = axΒ² + bx + c will have a minimum/maximum value at x = - b/2a. That's where the gradient of f, defined by f'(x) is 0.
21/05/2022
21/05/2022| As we approach the end of term 2, are you ready to ace your mid-year/june examinations ? π
Test your knowledge on:
Grade 10
Functions
Grade 11
Euclidean Geometry
Grade 12
Trigonometric functions
Solutions @ 23:00
09/03/2022
09/03/2022| Are you ready to ace your term 1 test? π
Test your knowledge on:
Grade 10
Exponential equations
Grade 11
Quadratic equations
Grade 12
General solutions
Solutions @23:00
05/03/2022
05/03/2022 | Evaluate yourself π
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Got it? Good for you.ππ»
βDidn't get it? Don't worry, read the explanation below and you'll do better next timeπ
Grade 10
1) The first thig we do when we have a fraction raised to a negative exponent, we invert the fraction then make the exponent positive. In other words, we swap the numerator and the denominator and make the exponent positive.
2) When we have a fraction a/b as an exponent, it means we take the b-th root and raise to the power of a. That is why we took the 4-th root and raised to the power of 3.
3) Simplify inside the brackets by getting rid of the 4-th roots and raise the answer to the power of 3.
Grade 11:
1) First thing we do when we solve quadratic inequalities is to simplify our equation to a standard form, that is: axΒ² + bx + c, and make sure that we only have 0 on our right hand side.
Thus, 3xΒ² + x β 4 β€ 0 is in standard form.
2) Factorise
(3x + 4)(x β 1) β€ 0
Just like when you solve for x, without the inequality sign, i.e (3x + 4)(x - 1) = 0, our critical values will be our roots or our x-intercepts of the graph y = 3xΒ² + x β 4. Hence:
x = β4/3 or x = 1
3) Draw your parabola or number line.
Since we are only looking for the x-values where y β€ 0, it means we want the x-values where the graph is below the x-axis (y = 0 line). Hence, those x-values are between β4/3 and 1.
4) Thus, our solution:
β4/3 β€ x β€ 1
Grade 12
1) A geometric convergent series is a series that has a limit or approaches a certain constant. This happens only when the constant ratio of the series is between β1 and 1, that is β1 < r < 1
2) Find your constant ratio, substitute in the inequality
β1 < r < 1 then solve for x
3) After solving for x:
β1 < 2x + 3 < 1, we find that the series will converge when x is between β2 and 1.
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05/03/2022
05/03/2022| Are you ready to ace your term 1 test? π
Test your knowledge on:
Grade 10
Exponents
Grade 11
Quadratic inequalities
Grade 12
Sequences & series
Solution @23:00
01/02/2022
Solutions for Dailly challenge 01/01/2022. Continue reading for explanations.
Grade 10:
1st step: Let x = 5.4`3`2`
x = 5.432432432...
2nd step: Multiply both sides by 1000. Why? Because we have 3 recurring digits aftet the coma. (4`3`2`) 3 digits > 1000 (3 zeros).
Then we have:
1000x = 5432.432432432...
3rd step: Subtract the first equation from the second equation:
1000x β x = 5432.432432432... β 5.432432432...
We remain with :
999x = 5427 then solve for x.
..................
Grade 11
1st step:
Expand the bases on the numerator. Why? Because we have addition of exponents and we know that they are as a result of same bases multiplying.
2nd step:
Factor out the common factor 3βΏ. Then simplify
..................
Grade 12:
1st step:
You know that it's a quadratic sequence (given).
You know that the general n-th term of a quadratic sequence is given by: Tn = anΒ² + bn + c
Where:
2a = second difference (common)
3a + b = first term of the first difference
a + b + c = first term of the sequence
2nd step:
Solve for a, b and c to find the Tn of the sequence.
3rd step:
Substitute n = 26 to find the 26th term of the sequence.
πβΊοΈ
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01/02/2022
Daily Challenge 01/02/2022.
Exercise your mind by solving the problem corresponding to your grade.
Post your answers in the comment box. Solutions will be posted at 21:00π
17/01/2022
Grade 10 β 12 Mathematics pace setters! Make sure not to fall behind the schedule π
06/11/2021
Lol, I like the examiner π₯π₯π₯Did you get it? Please if you didn't get it forget about itπ