12/03/2014
SAT Official Question of the Day: "On the last day of a one-week sale, customers numbered 149 through 201 were waited on. How many customers were waited on that day?"
See the explanation here: http://sat.collegeboard.org/practice/sat-question-of-the-day?questionId=20141203&tq=1 It's exactly the explanation I would have given.
The answer is 53. Why? 201 - 149 = 52, right? So, why isn't it 52? I'll get to that, but first let's see why you should NOT choose 52, even if you don't know what the right answer is. Because it's TOO EASY! This test, the SAT, is a test you take to get into COLLEGE, not 3rd grade! Do you really think there would be a question on the SAT for which you just had to subtract the two numbers? No. So, in this case, the best strategy is to eliminate the answer that is 'too easy'.
So then, why do we add 1 to obtain 53? Consider that this question is really: 'How many integers are there from 149 to 201?' You don't really want to count them all, and you know that 201 - 149 is 'too easy'. Let's make this into a simpler question, so we can find a rule:
How many integers are there from 3 to 6? Count them: {3, 4, 5, 6}. There are four integers. Yes, 6 - 3 = 3, but this only counts the spaces between the numbers. You also need to count either the first or last number, which has not yet been included. That's the reason for the 'plus one'.
Now, generalize. For integers a and b, there are are (b - a + 1) integers from a to b, inclusive.
Apply it to the current problem, and your answer is 201 - 149 + 1 = 53.
And NOW, you will get *every* problem like this one correct from now on.
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