10/02/2024
Question 1:
The distance-time graph for a car is shown below.
distance-time graph showing a car starting at rest, accelerating, moving at a constant speed, and then deceleratingOpens in a new window
www.toppr.com
distance-time graph showing a car starting at rest, accelerating, moving at a constant speed, and then decelerating
What is the car's acceleration between 0 and 5 seconds?
What is the car's speed at 10 seconds?
How far has the car traveled in 15 seconds?
Solution:
The car's acceleration between 0 and 5 seconds is equal to the slope of the line in that section of the graph. The slope of the line is rise/run = 5/5 = 1. Therefore, the car's acceleration is 1 m/s².
The car's speed at 10 seconds is equal to the value of the y-coordinate at that point on the graph. The y-coordinate at 10 seconds is 10, so the car's speed is 10 m/s.
The car has traveled a total distance of 25 m in 15 seconds. This can be found by calculating the area under the graph between 0 and 15 seconds.
Question 2:
A train leaves a station and travels at a constant speed for 10 minutes. It then accelerates at a rate of 2 m/s² for 5 minutes. The train then travels at a constant speed for another 10 minutes.
Draw a distance-time graph to represent the train's journey.
What is the train's maximum speed?
How far does the train travel in total?
Solution:
The distance-time graph for the train's journey is shown below.
distance-time graph showing the train traveling at a constant speed for 10 minutes, accelerating for 5 minutes, and then traveling at a constant speed for 10 minutesOpens in a new window
www.toppr.com
distance-time graph showing the train traveling at a constant speed for 10 minutes, accelerating for 5 minutes, and then traveling at a constant speed for 10 minutes
The train's maximum speed is 10 m/s. This is the speed at which the train is traveling when it is accelerating.
The train travels a total distance of 75 m in its journey. This can be found by calculating the area under the graph.
Question 3:
A car is moving at a speed of 20 m/s when it sees a red light and brakes. The car comes to a stop in 5 seconds.
Draw a distance-time graph to represent the car's journey.
What is the car's deceleration?
How far does the car travel before it stops?
Solution:
The distance-time graph for the car's journey is shown below.
distance-time graph showing the car traveling at a constant speed, decelerating, and then coming to a stopOpens in a new window
physics-ref.blogspot.com
distance-time graph showing the car traveling at a constant speed, decelerating, and then coming to a stop
The car's deceleration is equal to the slope of the line in the deceleration section of the graph. The slope of the line is rise/run = -40/5 = -8. Therefore, the car's deceleration is -8 m/s².
The car travels a total distance of 100 m before it stops. This can be found by calculating the area under the graph.
I hope this helps! Let me know if you have any other questions.
http://scienceshorts.net Ah, Bob's up to his old tricks again. Can't blame him though, can you...Bob's Speed-Time graph & acceleration conclusion: http://you...