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The solution

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Solution to this integral

Find the roots of the equation x³+64=0...
Leaving ans in the form a+¡b

If cos²θ = 12/13; find 1 + cot²θ.

Integrate 5/(xInx) dx

Solution
§ 5/(xInx) dx = 5§1/(xInx)dx
Put u = Inx, du/dx = 1/x, dx = xdu
5§1/(x.u) . xdu
5§1/u du
5(Inu) + c
Put u = Inx
5In(Inx) + c

§ 5/(xInx) dx = 5In(Inx) + c

Integrate 5/(xInx) dx

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