21/10/2022
Convert Local Mean Time ( ) To Local Zone Time ( ) ... 👇
The LMT of sunrise as tabulated in the Nautical Almanac indicates 06h 00 min.
You are at longitude 116° 00' E.
What will be the LZT of sunrise?
Given:
LMT = 06 h 00 min
Longitude = 116° 00' E
What is asked?
LZT of sunrise ???
Solution:
1. Converting arc to time.
We have to divide the longitude by 15.
116° 00' ÷ 15 = 07 h 44 min
2. Since the longitude is east, we have to subtract 07 h 44 min to the LMT.
The result of that will be the GMT.
LMT = 06 h 00 min ( + 24 hours)
-07 h 44 min
--------‐---------------
GMT= 22 h16 min
3. GMT to LZT. 07 h 44 min can now be rounded off to 0800H since the minutes is more than 30.
We have to add it to the GMT to get the LZT since the longitude is east..
GMT = 22:16 H
+08:00 H
-----------------
30:16 H
- 2400 H
------------------
LZT = 06 h16 min
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Finding Of Place B
The ZT at Place A is 0800.
If the longitude of A is 49° 30' W, what is the ZT of Place B in longitude 83° 15' W?
Given:
Longitude of Place A = 49° 30' W
Longitude of Place B = 83° 15' W
ZT at Place A = 0800
Find:
of Place B ???
Solution:
1. Divide the longitude of Place A and Place B by 15.
By doing this, we are converting it to ZD.
Longitude of Place A = 49° 30' W ÷ 15 = 3° 18'.
The minutes is less than 30, therefore the ZD would be +3.
Longitude of Place B = 83° 15' W ÷ 15 = 5° 33'. The minutes is more than 30,
therefore the ZD would be +6.
2. Next is to subtract the ZD of places A and B to get the time difference.
ZD of Place B = +6
ZD of Place A = - +3
Time difference = 3
4. We can solve now for the ZT of Place B.
ZT of Place A = 0800
Time Difference = - 3
(subtract since Place B is located west of A)
05:00 is the ZT of Place B
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