infinite.aximi

infinite.aximi →Daily video
→Daily new questions
→Daily new challenge
→FOLLOW FOE MORE.....

29/09/2026

"Please solve for the total length marked by the question mark (?) in the image. Show all step-by-step calculations.
Diagram Details:
Diagram Details:
A large triangle is divided into two right-angled triangles by a vertical height line (perpendicular to the base).
Left Right-Triangle:
Base length = 20 m
Bottom-left angle = 60°
Right Right-Triangle:
Top angle (between the vertical line and the hypotenuse) = 60°
Find the total base length of the main triangle."

28/09/2026

Answer in comment box and follow for more questions 😀


Based on the Exterior Angle Theorem, the measure of an exterior angle of a triangle is equal to the sum of the measures of its two remote interior angles.
Step-by-Step Solution
* Set up the equation:

* Combine like terms:

* Subtract 30 from both sides:

* Divide by 15:

Verification
* Lower-left interior angle: 5(6) + 10 = 40^\circ
* Top interior angle: 10(6) + 20 = 80^\circ
* Sum of interior angles: 40^\circ + 80^\circ = 120^\circ (matches the exterior angle)
The value of x is 6.

27/09/2026

Easy peasy solve and answer in comment and you all know that 3rd October is a exam helding from my side so all ready 🗿
Sigmas .

26/09/2026

Answer in comment fast ⏩😄
If you don't know then check privious questions 😀
Answer in there
And in 3rd October there was a exam form my side any body was interested ✒️
Then comment yes😄
Fast fast

25/09/2026

Answer in comment box and follow for more questions 😀


To find the value of x, assuming ABCD is a parallelogram:
* Find \angle EFC:
Since B, F, and C lie on a straight line, the angles at point F form a linear pair:

* Determine the angles of \triangle EFC:
The tick marks indicate that side FC is equal in length to side EC (FC = EC). Therefore, \triangle EFC is an isosceles triangle with base angles \angle EFC and \angle FEC:

* Find the interior angle \angle C:
The sum of angles in \triangle EFC is 180^\circ:

* Find x (\angle D):
In a parallelogram, consecutive angles are supplementary:

Thus, x = 80^\circ.

23/09/2026

You can find the value of x then comment answer 😄
In any body cand find then comment answer for learn the answer.😄
I'm always with you but my views day by day falling Down what happened my vive 😔 just support.
There is no prompt.

22/09/2026

Here is the step-by-step breakdown to solve the math puzzle in the image! 📐✨
📝 Given Equation
🔢 Step-by-Step Solution
* Multiply both sides by 6 to eliminate the fraction ✖️:

* Add 4 to both sides to isolate 2x ➕:

* Divide both sides by 2 to find x ➗:

🎉 Final Answer
x = 8 🎯

Would you like to go to next
Comment next👉

21/09/2026

Here is a breakdown to solve for the unknown angle x from the geometry puzzle: 📐✨
1. Find the Third Angle in the Top Triangle 🔺
* The sum of angles in any triangle is 180°.
* Top triangle angles: 40° and 40°.
* Third angle = 180° - (40° + 40°) = 100°.
2. Use Vertically Opposite Angles ✖️
* The top triangle and bottom triangle intersect to form vertical (opposite) angles.
* Since vertical angles are equal, the top angle inside the bottom triangle is also 100°.
3. Find the Inside Angle of the Bottom Triangle 📐
* The sum of angles in the bottom triangle is also 180°.
* We have 100° (top) and 50° (bottom-left).
* The bottom-right interior angle = 180° - (100° + 50°) = 30°.
4. Calculate Angle x 🎯
* The interior bottom-right angle and x form a straight line (180°).
* 🎉 Final Result
X=150

20/09/2026

Before Verry difficult yes ✒️ after verry easy 🗿

19/09/2026

Answer in comment
This image presents a geometry puzzle asking to solve for the missing angle x^\circ.
Problem Setup
Label the vertices of the large triangle as follows:
* Top vertex: A
* Bottom-left vertex: B
* Bottom-right vertex: C
* The interior point on side AC: D
Given values and equal segment markings:
* * * BD = DC = BC (indicated by the double hash marks on BD, DC, and BC)
* Step-by-Step Solution
1. Analyze \triangle BCD
Since BD = DC = BC, \triangle BCD is an equilateral triangle.
* All interior angles of \triangle BCD are 60^\circ.
* Therefore, \angle BCD = \angle CDB = \angle DBC = 60^\circ.
2. Analyze the main triangle \triangle ABC
* Total sum of angles in \triangle ABC = 180^\circ.
* We know \angle BAC = 45^\circ and \angle BCA = 30^\circ (Note: Here, C, D, A are collinear, so \angle BCA = 30^\circ).
* Therefore, the entire angle at B is:

3. Express \angle ABC in terms of its parts
The total angle at vertex B is composed of \angle ABD and \angle DBC:

Substitute the known values:

Final Result

Address

Ramgarh

Website

Alerts

Be the first to know and let us send you an email when infinite.aximi posts news and promotions. Your email address will not be used for any other purpose, and you can unsubscribe at any time.

Shortcuts

Share

Category