EquationbyManish

Here is ver basic animation for understand word problem. Hope this help students to have good understanding of the subject.

Grade : 8th CBSE
Subject : Mathematics
Topic : 12 Exponents & Powers
Exercise: 2.2
Que no : 4

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Learn Exponent & Power with Equationbymanish

Topic: 12.Expoenent & Power
Subject: Mathematics

Who can attend: Anyone who wants to understand the exponent & power

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Grade: 8th
Subject: Maths - 2
Chapter: 02 Parallel lines and transversals
Board: State

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Call or WhatsApp us on +91 8850018970 or +91 9867799174

This video covers how to solve problems on Pythagoras Theorem using Analytical and Critical thinking, as explained by Manish Sir.

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Call or WhatsApp us on +91 8850018970 or +91 9867799174

27 Questions to Trigger Analytical Thinking & Critical Thinking in every student for any problem:

1. Question: What is given in problem?
Answer:
a. Some Triangles 𝛥PMN, 𝛥PMQ, 𝛥PQR, 𝛥PRN
b. Some sides: PQ, MQ, QR & RN
c. All given sides are equal & equal to "a"

2. Question: What we need to Find or prove?
Answer: To prove: PN = (Square root of 3) x a

3. Question: Which triangle we need to consider to find PN?
Answer: 𝛥PSN

4. Question: Why to consider 𝛥PSN & not others?
Answer: 𝛥PSN is a right angle triangle with PN as hypotenuse & we can apply Pythagoras theorem in it.

5. Question: Can you apply the Pythagoras theorem in PSN & tell the result?
Answer: PN^2 = PS^2 + SN^2

6. Question: So to find PN we need to find PS & SN, right?
Answer: Yes Sir

7. Question: Lets think about SN first, Can you tell me how to find that? Answer: One way is SN = SR + RN

8. Question: Do we know the value of RN?
Answer: Yes sir, it is given.

9. Question: How much is RN?
Answer: A

10. Question: Pending is to find the value of SR. Can anyone think about how to find it?

11. Question: Other than right angle triangle, can we see any other information given?

12. Question: Can we see any other types of triangle from given figure?

13. Question: What do you think of triangle PQR?

14. Question: What are the sides of triangle PQR?
Answer: All are equal to A.

15. Question: So what does this mean? Which type of triangle it is?
Answer: Equilateral triangle

16. Question: What is the property of equilateral triangle we studied, in terms of perpendicular drawn on any segment
Answer: In an equilateral triangle, the median, angle bisector and perpendicular are all the same

17. Question: This means PS is the perpendicular bisector of QR?
Answer: Yes

18. Question: Does that mean, QS = SR?
Answer: Yes

19. Question: If QR = 20, how much is SR?
Answer: SR = 10

20. Question: If QR = 10, how much is SR?
Answer: SR = 5

21. Question: In our case QR = a, how much will be SR?
Answer: SR = a/2

22. Question: Exactly, we are done with SR, now only pending is to find PS. Which triangle we need to consider to find PS?
Answer: Either PSR or PSQ as both involves PS.

23. Question: Exactly, we can use any of them, lets consider PSR, can we apply Pythagoras theorem here?
Answer: Yes

24. Question: What is the result?
Answer: PR^2 = PS^2+ SR^2

25. Question: Do we know PR here?
Answer: Yes

26. Question: How much it is?
Answer: a, It is Given

27. Question: How about SR, do we know it?
Answer: Yes, we just found it as a/2 Now we know PS, SN, can we find PN using Pythagoras theorem!

Enjoy!