02/03/2026
⚡ HOOKE’S LAW CHALLENGE: Can You Calculate the Force?
A spring with a spring constant of 250 N/m is stretched by 0.04 m. What force is applied to the spring?
This question tests your understanding of one of the most important relationships in elasticity — Hooke’s Law, expressed as:
F = kx
Where:
🔹 F = Force applied (Newtons, N)
🔹 k = Spring constant (N/m)
🔹 x = Extension (metres, m)
This formula is a core concept in KCSE and IGCSE Physics, and it appears frequently in exams because it connects theory with real-world applications such as:
✔ Spring balances
✔ Shock absorbers in vehicles
✔ Measuring forces in laboratories
✔ Engineering and material testing
When a force is applied to a spring, the extension produced is directly proportional to the force — provided the elastic limit is not exceeded. This proportional relationship is the foundation of Hooke’s Law and is represented by a straight-line graph passing through the origin.
This question challenges you to:
• Identify the correct formula
• Substitute values correctly
• Apply proper units
• Understand the relationship between force and extension
Many students lose marks not because they don’t know the formula, but because they fail to apply it correctly. Mastering these simple calculations builds confidence for tackling more advanced topics such as:
🔹 Elastic potential energy
🔹 Force-extension graphs
🔹 Young’s modulus
🔹 Oscillations and SHM
Physics is not about memorizing — it’s about understanding relationships.
Train your mind to think like a physicist. Every calculation strengthens your problem-solving skills and prepares you for exam success.
Question: A spring has a spring constant of 250 N/m. If the extension is 0.04 m, what force is applied?
Comment your answer below before checking the solution. Let’s see who gets it correct! 🎯
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