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CSIR -UGC NET MATHEMATICAL SCIENCE | | COMPLETE DETAILED SOLUTIONS || YEAR - 2020 | | PART - 2
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How to prepare for UGC NET 2020?
UGC NET is considered one of the toughest exams to clear because a large number of candidates appear for this exam every year. The aspiring candidates may follow the tips mentioned below in order to perform well in the UGC NET 2020 exam.
A study from good quality help books which are written by renowned writers.
Solve previous year’s question papers and mock tests, so that you can simulate the exam and understand exam pattern in a better way.
Make short notes for all the important topics and revise from them regularly.
Read current affair magazines and newspapers.
Think positive and stay away from any type of anxiety.
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CSIR NET previous year solved paper, EXPLAINED in an easy way Sourav Sir's Classes
https://www.youtube.com/watch?v=GmxLiQswVlQ
CSIR NET previous year solved paper, EXPLAINED in an easy way @Sourav Sir's classes CSIR UGC NET is a national level entrance examination for Junior Research Fellowship (JRF) and Eligibility for Lectureship (LS) in the field of Science inclu...
Crucial information at a glance....
The online submission of UGC NET 2019 application form will start from 16th March 2020.
It will be only possible to apply for UGC NET in online mode. If you submit your application through any other mode then it won’t be accepted.
Candidates must submit only one application for the exam.
The official website to access UGC NET application form is ntanet.nic.in.
Candidates must provide their own email address and mobile number in the application form.
UGC NET will be held as a Computer Based Test (CBT) only.
The exam will comprise of two papers. All the questions will be objective type questions only. Candidates need to take the exam over a break of 30 minutes between them.
Candidates’ eligibility only ‘for Assistant Professor’ or for ‘both Junior Research Fellowship and Assistant Professor’ will depend upon how they performed in both the papers.
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Relativistic particle problem CSIR NET previous year question SOLVED Sir's Classes
https://www.youtube.com/watch?v=Ad3jzBvDh7c
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UGC NET 2020 Selection Procedure....
Candidates qualifying the entrance test of UGC NET 2020, will be selected in the subject wise and category wise merit list published online. Top 6% of total students who have appeared for both the papers in the test will be considered qualified in the entrance test.
Admission into various Indian Universities or Institutions for the position of Assistant professor or JRF will be offered on the basis of cut off score secured as per their categories. Top 15% candidates from each category and subject will be selected and declared eligible for Assistant Professor Position only.
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UGC NET 2020 Cut Off....
UGC NET 2020 Cut Off will be published online by the authority after the entrance test. Separate category wise and subject wise merit list will be drawn for the students successfully securing the cut off marks.
In the below table we have mentioned the cut off marks for various categories as per the last year trends:
Category Minimum qualifying marks (in %)
Paper – I Paper – II
General candidates 40% 40%
OBC – NCL/PWD/ST/SC candidates 35% 35%
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CSIR NET PART B & PART C SOLVED, previous year questions with full solution
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UGC NET 2020 Scorecard...
The scorecard will be released along with the release of results. UGC NET 2020 Scorecard will mention various important details about the candidate and the entrance exam.
These details will include candidate’s name, course name, hall ticket number, total marks, marks secured by the candidate in paper I and II, rank scored and percentage.
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UGC NET 2020 Result....
After the completion of exams and release of answer key, the board will announce the result. The results will be released on 5th July 2020 for June session exam in the second week of January 2021 for December session.
Students can check their result through online mode by submitting their roll number and date of birth. Only the candidates who will qualify the test by securing the cut off marks will be called for the counselling process.
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CSIR NET previous year solved questions, EXPLAINED IN DETAIL
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UGC NET 2020 Answer Key....
After completion of the entrance exam, board will publish the UGC NET 2020 Answer key. Candidates will be able to download the Answer key through online mode.
The Answer key will be released for both Paper – I and II in various sets containing all the right answers of the questions asked in the exam paper. Candidates can also challenge the answer key in case they are not satisfied with the answers given in it.
After considering the challenges, final answer key will be released by the board.
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NEWTON'S FORWARD DIFFERENCE METHOD for CSIR NET, previous years questions with full solutions
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UGC NET 2020 Admit Card...
UGC NET 2020 Admit card is an important document which must be carried by the appearing students on the exam day. No candidate will be allowed to take exam without showing the admit card to the invigilator.
The Admit card will be released on 15th May 2020 for June session exam and in the 3rd week of November 2020 for December session exam. It will be available through online mode only by entering application number and password.
In case any problem arises at the time of downloading the admit card, candidates can contact the officials to rectify the problem. Also, if any candidate has forgotten his password or application number, he/she can retrieve it back by clicking the given option of forgot password answering various questions.
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CSIR NET PART B & PART C previous year questions SOLVED and EXPLAINED
https://www.youtube.com/watch?v=GUiWhQ4AI98
UGC NET 2020 Preparation Tips...
Below we have provided preparation tips with the help of which candidates can score good marks and qualify the test:
Check the syllabus, exam pattern and marking scheme of UGC NET before starting your exam preparation.
Start your exam preparation early. It will give enough time in the end for revision.
Prepare notes and go through these notes every day to refresh your memory and remember the studied topics.
Study from the study materials which are mostly recommended by the experts and qualified students.
Solve previous year question papers and sample papers. This will give an idea to the candidates about the question trends.
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CSIR NET previous year paper SOLVED AND EXPLAINED in detail
https://www.youtube.com/watch?v=WsSVNR-RfQ0
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UGC NET 2020 Syllabus...
UGC NET 2020 Syllabus for Paper I and Paper II can be checked by the candidates through online mode. It will vary as per the subjects chosen by the candidate at the time of registration.
Paper I of UGC NET 2020 will contain questions of generic nature, intending to assess the teaching/research aptitude of the students. This paper will test the candidate’s knowledge in reasoning ability, comprehension, divergent thinking and general awareness.
Paper II of UGC NET 2020, will contain various topics from the subjects selected by the candidates. The topics will be related to Bachelors and Masters level syllabus.
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CSIR NET previous year paper with full solution in details, Check out now
https://www.youtube.com/watch?v=0xLcGc2N5lk
CSIR NET previous year paper with full solution in details, Check out now CSIR UGC NET is a national level entrance examination for Junior Research Fellowship (JRF) and Eligibility for Lectureship (LS) in the field of Science inclu...
UGC NET 2020 Exam Pattern...
Check the complete UGC NET 2020 Exam Pattern below, before starting you exam preparation:
Exam Date: UGC NET 2020 Exam will be conducted in the second week of July 2020 for July Session and third week of December 2020 for December Session.
Exam Mode: The entrance test will be organized in Online CBT mode.
Number of Papers: There will be two papers for the exam – Paper I and Paper II.
Number of Questions: Total of 150 questions will be there in the exam paper. 50 questions in Paper I and 100 questions in Paper II.
Type of Questions: The question paper will contain multiple choice type questions.
Language Medium: The question paper will be available in the medium language of English and Hindi.
Time Duration: Paper I will be of 1 hour duration while Paper II will be of 2 hours.
Total Marks: Paper 1 will be of 100 marks and Paper II will be of 200 marks.
Marking Scheme: For every correct answer, 2 marks will be given. There will be no provision of negative marking for incorrect answer.
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CSIR NET Previous years problem with solutions in details
https://www.youtube.com/watch?v=aosZqNER-RU
CSIR NET Previous years problem with solutions in details #souravsirclasses CSIR UGC NET is a national level entrance examination for Junior Research Fellowship (JRF) and Eligibility for Lectureship (LS) in the field of Science inclu...
UGC NET 2020 Eligibility Criteria....
Candidates must fulfill the below given UGC NET 2020 Eligibility Criteria before applying for the exam:
Academic Qualifications:
Qualifying Exam: Applying candidate should own Master’s degree or its equivalent from a board or university recognized by UGC.
Qualifying Marks: Candidate must have secured minimum of 55% marks (50% for ST/SC/OBC/PwD) in the Master’s degree in streams such as Social Science, Humanities, Computer Science & Applications and Electronic Science.
Appearing Candidate: Candidates who are in their final year of qualifying exam can also apply.
Age Criterion:
There is no age limit for the position of Assistant Professor. However, in case of JRF the age of the applicant must not be more than 30 years as on January 1, 2020. 5 years of relaxation is given to reserved candidates.
For LLM Degree possessing candidates, 3 years of age relaxation will be given.
Candidates, who have served in the armed forces, will be given 5 years of age relaxation.
Exemption (Eligibility for Assistant Professor):
Candidates must clear their NET/SLET/SET exam in order to be eligible for the post of Assistant Professor in various Universities or institutions.
Candidates successfully clearing their SET before June 1, 2002 recognized by UGC will be exempted to appear in the exam.
Candidates who have passed the UGC/CSIR JRF examination earlier than the year 1989 are exempted to appear for the test.
Candidates who are awarded with a PhD Degree by UGC as per the minimum standards and process for the award will be exempted from the requirement of the minimum eligibility condition of NET/SET/SELT for appointment as Assistant Professor in Universities/ Colleges/ Institutions.
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CSIR NET previous year questions with full solution, Explained in details
https://www.youtube.com/watch?v=fnprMdTsNR0
CSIR NET previous year questions with full solution, Explained in detals CSIR UGC NET is a national level entrance examination for Junior Research Fellowship (JRF) and Eligibility for Lectureship (LS) in the field of Science inclu...
UGC NET 2020 Application Correction
In case candidates have made mistakes while filling details in the application or the uploading images, corrections can be made. The board will open the application correction window after the completion of application process.
Students can make corrections through online mode. In case any error is found in the uploaded images, a mail or message will be sent to the candidate’s registered mobile number.
The corrections in the application must be done by the students before the last date otherwise the forms will get rejected.
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CSIR NET BOOLEAN FUNCTION previous year questions with full solution
https://www.youtube.com/watch?v=-Tbc_X5BsQg
CSIR NET BOOLEAN FUNCTION previous year questions with full solution #souravsirclasses CSIR UGC NET is a national level entrance examination for Junior Research Fellowship (JRF) and Eligibility for Lectureship (LS) in the field of Science inclu...
Application Fee:
Applicants have to pay the below application fee as per their categories:
For General Candidates – Rs.1000
For OBC- NCL Candidates – Rs.500
For ST/SC/PwD Candidates – Rs.250
Mode of Payment: Applying candidates can pay the application fee through debit/credit card or E-Challan at the nearest ICICI/Syndicate Bank/Canara Bank.
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CSIR NET previous year questions solved and explained in details
https://www.youtube.com/watch?v=MAMbOuXgqv8
CSIR NET previous year questions solved and explained in details #souravsirclasses CSIR UGC NET is a national level entrance examination for Junior Research Fellowship (JRF) and Eligibility for Lectureship (LS) in the field of Science inclu...
UGC NET 2020 Application Form
Candidates can check below the complete details of UGC NET 2020 Application Form:
The Online Application Form of UGC NET 2020 will be released on 16th March 2020 for the June session exam and in the first week of September 2020 (December Session).
Candidates can fill the application form by following various steps – Online Registration, Filling the application form, uploading of scanned images and payment of application fee.
Last date to fill the application form online is till 16th April 2020 for the June exam and in the last week of September 2020 for December Session.
Candidates can also correct mistakes in the details of the application form when the board will open the correction facility.
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CSIR NET previous year question solved and explained in detail
https://www.youtube.com/watch?v=YSgJfakhUII
CSIR NET previous year question solved and explained in detail #souravsirclasses CSIR UGC NET is a national level entrance examination for Junior Research Fellowship (JRF) and Eligibility for Lectureship (LS) in the field of Science inclu...
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