16/04/2023
Work done by forces in Sun Earth system -
As an object moves in an elliptical path, its position, velocity, and acceleration are constantly changing. The work done by forces acting on the object depends on these factors and can be calculated using the work-energy principle.
Let's consider the example of the Earth moving in its elliptical orbit around the Sun. The primary force acting on the Earth is the gravitational force exerted by the Sun. At different positions in the orbit, the magnitude and direction of the gravitational force changes, which affects the work done by the force.
Perihelion: At the point of closest approach to the Sun (perihelion), the gravitational force is the strongest, and the Earth is moving fastest. At this position, the force is doing the most work on the Earth as it pulls the planet towards the Sun. As the Earth moves closer to the Sun, the gravitational potential energy decreases, and the kinetic energy increases.
Aphelion: At the point of furthest distance from the Sun (aphelion), the gravitational force is the weakest, and the Earth is moving slowest. At this position, the force is doing the least work on the Earth as it pulls the planet away from the Sun. As the Earth moves away from the Sun, the gravitational potential energy increases, and the kinetic energy decreases.
In between: In the positions in between perihelion and aphelion, the work done by the gravitational force is somewhere in between the maximum and minimum values. The closer the Earth is to the Sun, the greater the work done by the gravitational force, and the further away the Earth is, the less work is done.
Overall, the net work done by the gravitational force over one complete orbit of the Earth around the Sun is zero, as the Earth returns to its starting position and the gravitational potential energy is unchanged. However, the amount of work done by the force varies depending on the position of the Earth in its elliptical orbit.
The work-energy principle states that the work done by a force on an object is equal to the change in the object's kinetic energy. Mathematically, this can be expressed as:
W = ΔKE
Where W is the work done by the force and ΔKE is the change in the object's kinetic energy.
For an object moving in an elliptical path, its kinetic energy is given by:
KE = (1/2)mv^2
Where m is the mass of the object and v is its velocity.
The velocity of an object moving in an elliptical path can be calculated using Kepler's second law, which states that the area swept out by a line connecting the object to the center of mass of the system is constant. Mathematically, this can be expressed as:
r^2(dθ/dt) = h
Where r is the distance between the object and the center of mass, θ is the angle between the line connecting the object to the center of mass and a reference direction, t is time, and h is a constant called the specific angular momentum.
Using this equation, the velocity of the object can be calculated as:
v = h/r
The distance between the object and the center of mass of the system varies in an elliptical path, and can be calculated as:
r = a(1 - e^2)/(1 + e*cos(θ))
Where a is the semi-major axis of the elliptical path, e is the eccentricity of the path, and θ is the angle between the line connecting the object to the center of mass and a reference direction.
Using these equations, the work done by a force at a given position in an elliptical path can be calculated by first finding the velocity and distance at that position, and then calculating the change in kinetic energy as the object moves from that position to another position in the path.