If DE || BC then AD/AB = AE/AC
in ∆ABC.
AD/AB = AE/AC if DE || BC in ∆ABC.
In ∆ABC if DE || BC then AD/AB = AE/AC
If a line intersects sides AB and AC of a ∆ABC at D and E respectively and is parallel to BC, prove that AD/AB = AE/AC.
Maxone Education
"The way of success"
Triangles |
Part-3 |
Converse of Thales's theorem |
थेल्स प्रमेय का विलोम।
Converse of BPT theorem |
BPT प्रमेय का विलोम।
Converse of basic proportionality theorem |
आधारभूत समानुपातिक प्रमेय का विलोम।
#थेल्स_प्रमेय_का_विलोम
Triangles |
Part-2 |
Thales's theorem |
BPT theorem |
Basic proportionality theorem |
आधारभूत समानुपातिकता प्रमेय |
#आधारभूतसमानुपातिकताप्रमेय
#थेल्सकाप्रमेय
Triangles | त्रिभुज |
Part-1 |
Similarity of figures |
आकृतियों की समरूपता
Arithmetic progression |
Part-7 |
Even & odd consecutive terms of an AP|
AP के क्रमागत सम और विषम पद |
maths
#समान्तरश्रेणी #समान्तरश्रेढ़ी
Arithmetic progression |
Part-6 |
Relationship between three consecutive terms of an AP |
समांतर श्रेणी के तीन लगातार पदों में संबंध |
maths
#समान्तरश्रेणी #समान्तरश्रेढ़ी
Superfast multiplication trick |
Multiplication of 11 superfast trick |
Square trick of numbers having last digit 5 |
Square trick |
Maths trick |
Arithmetic progression | समान्तर श्रेणी |
Part-1|
Introduction |
#समान्तरश्रेणी #समान्तरश्रेढ़ी Education
Quadratic equations |
Part-5 |
Nature of roots |
मूलों की प्रकृति |
Quadratic equations | Part-4 | Solution of a quadratic equation by quadratic formula |
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