A man went downstream for 28 km in a motor boat and immediately returned. It took the man twice as long to make the return trip. If the speed of the river flow were twice as high, the trip downstream and back would take 672 minutes. Find the speed of the boat in still water and the speed of the river flow.
Explanation:
Let the speed of the boat = p kmph
Let the speed of the river flow = q kmph
From the given data,
2 x 28p + q = 28p − q
=> 56p - 56q -28p - 28q = 0
=> 28p = 84q
=> p = 3q.
Now, given that if
283q + 2q + 283q − 2q = 67260=> 285q + 28q = 67260=> q = 3 kmph=> x =3q = 9 kmph
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A boatman can row 96 km downstream in 8 hr. If the speed of the current is 4 km/hr, then find in what time he will be able to cover 8 km upstream ?
Ans
Speed in downstream = 96/8 = 12 kmph
Speed of current = 4 km/hr
Speed of the boatman in still water = 12 – 4 = 8 kmph
Speed in upstream = 8 – 4 = 4 kmph
Time taken to cover 8 km upstream = 8/4 = 2 hours
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