Knowledge Gate Academy

02/04/2026

Title
motion | Class 9 Physics | Concept clarity | Knowledge Gate Academy

Today we are explaining motion in a simple and student-friendly way so that even difficult physics feels easier to understand.

Look at this topic in 3 easy parts:

1. Core idea
This part explains the central rule or principle behind the topic.

2. Real-life connection
Physics becomes easier to remember when we connect it with everyday observations.

3. Exam importance
In board exams, students may be asked for definitions, explanations, differences, and examples.

Quick learning tip:
Do not just memorize the topic. Understand the rule, the reason, and one clear example.



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Knowledge Gate Academy | 6 followers on LinkedIn. Think. Learn. Excel | Knowledge Gate Academy enables students to master core science concepts with exam-ready strategies. We focus on clear fundamentals, practical problem solving, and performance improvement. Based in Karachi, we deliver structured....

16/03/2026

🧬 Biology XI – Chapter 1 | Biological Molecules
Topic: Proteins (Part 8)
👨‍🏫 Prof. Faraz Uddin

Proteins are essential biological molecules responsible for many important functions in living organisms. In this lecture, Prof. Faraz Uddin explains the concept of proteins in a simple and clear way for First Year (FSc) Biology students.

🎥 Watch the lecture:
https://youtu.be/h-M5vVJJ0Xs

Follow Knowledge Gate Academy for more Biology lectures, science concepts, and exam preparation videos.

Biology XI – Chapter 1 (Biological Molecules)Topic: Proteins – Part 8Instructor: Prof. Faraz UddinIn this lecture, Prof. Faraz Uddin explains the concept of ...

16/03/2026

🧬 Biology XI – Chapter 1 (Biological Molecules)
Topic: Proteins | Part 8
👨‍🏫 Lecture by Prof. Faraz Uddin

In this lecture, the concept of proteins is explained in a simple and clear way for FSc / First Year Biology students. A helpful session for understanding biological molecules and preparing effectively for exams.

Follow Knowledge Gate Academy for more Biology lectures, science concepts, and exam preparation videos.

14/03/2026

📘 **Physics XI – Conductivity Numerical | Current Electricity**

Given:
Length **L = 20 m**
Cross-sectional area **A = 1 mm²**
Resistance **R = 5 Ω**

Using the formula:

σ = L / RA

σ = 20 / [5 × (1 × 10⁻⁶)]

σ = **4 × 10⁶ S/m**
or **4 MS/m**

📚 Class XI Physics – Current Electricity
Clear concepts with **Knowledge Gate Academy**.

▶ Watch the short lecture:
https://youtube.com/shorts/R5LYqazsEZg?feature=share

YouTube:
Instagram: /knowledgegate.edu2026
TikTok: .edu

14/03/2026

📘 **Physics XI – Conductivity Numerical | Current Electricity**

Given:
Length **L = 20 m**
Cross-sectional area **A = 1 mm²**
Resistance **R = 5 Ω**

Using the formula:

σ = L / RA

σ = 20 / [5 × (1 × 10⁻⁶)]

σ = **4 × 10⁶ S/m**
or **4 MS/m**

📚 Class XI Physics – Current Electricity
Clear concepts with **Knowledge Gate Academy**.

▶ Watch the short lecture:
https://youtube.com/shorts/R5LYqazsEZg?feature=share

YouTube:
Instagram: /knowledgegate.edu2026
TikTok: .edu

📘 **Physics XI – Conductivity Numerical****Data:**Length **L = 20 m**Cross-sectional area **A = 1 mm²**Resistance **R = 5 Ω**Using the formula:σ = L / RAσ =...

14/03/2026

📘 **Physics XI – Work & Power Numerical | Model Paper 2026**

A man of **mass 70 kg** climbs a **height of 3 m** in **2 seconds**.
Find **Work Done** and **Power**.

Work = mgh
W = 70 × 9.8 × 3 ≈ **2058 J**

Power = W / t
P = 2058 / 2 ≈ **1029 W**

📚 Class XI Physics – Work & Power
Clear concepts with **Knowledge Gate Academy**.

▶ Watch the short lecture:
https://youtube.com/shorts/IpWlSKJQHqc?feature=share

YouTube:
Instagram: /knowledgegate.edu2026
TikTok: .edu

📘 **Physics XI – Model Paper 2026 | Work & Power Numerical (Part 2)**A man of **mass 70 kg** climbs a **height of 3 m** in **2 seconds**.Find **Work Done** ...

14/03/2026

📘 **Physics XI – Work & Power Numerical | Model Paper 2026**

A man of **mass 70 kg** climbs a **height of 3 m** in **2 seconds**.
Find **Work Done** and **Power**.

Work = mgh
W = 70 × 9.8 × 3 ≈ **2058 J**

Power = W / t
P = 2058 / 2 ≈ **1029 W**

📚 Class XI Physics – Work & Power
Clear concepts with **Knowledge Gate Academy**.

▶ Watch the short lecture:
https://youtube.com/shorts/IpWlSKJQHqc?feature=share

YouTube:
Instagram: /knowledgegate.edu2026
TikTok: .edu

14/03/2026

📘 **Physics XI – Model Paper 2026 | Work & Power**

A man of **mass 70 kg** climbs a **height of 3 m** in **2 seconds**.
Find **Work Done** and **Power**.

Work = mgh
W = 70 × 9.8 × 3 ≈ **2058 J**

Power = W / t
P = 2058 / 2 ≈ **1029 W**

📚 Class XI Physics – Work & Power
Clear concepts with **Knowledge Gate Academy**

▶ Watch the short lecture:
https://youtube.com/shorts/DVAxHIif6Fs?feature=share

YouTube:
Instagram: /knowledgegate.edu2026
TikTok: .edu

📘 **Physics XI – Model Paper 2026 (Section B)****Question:**A man of mass **70 kg** climbs a height of **3 m** in **2 seconds**.Find:• **Work done (W)**• **...

14/03/2026

📘 **Physics XI – Model Paper 2026 | Work & Power**

A man of **mass 70 kg** climbs a **height of 3 m** in **2 seconds**.
Find **Work Done** and **Power**.

Work = mgh
W = 70 × 9.8 × 3 ≈ **2058 J**

Power = W / t
P = 2058 / 2 ≈ **1029 W**

📚 Class XI Physics – Work & Power
Clear concepts with **Knowledge Gate Academy**

▶ Watch the short lecture:
https://youtube.com/shorts/DVAxHIif6Fs?feature=share

YouTube:
Instagram: /knowledgegate.edu2026
TikTok: .edu

14/03/2026

🎯 **At What Angle Does Range = Maximum Height? | Projectile Motion**

Do you know the launch angle at which the **range of a projectile becomes equal to its maximum height?** 🤔

Using projectile motion formulas and solving **R = H**, we get:

**tanθ = 4**

So the required angle is approximately **76°** 🚀

📚 Class XI Physics – Projectile Motion
Clear concepts with **Knowledge Gate Academy**.

▶ Watch the short lecture here:
https://youtube.com/shorts/EJSnHVOV2e4?feature=share

YouTube:
Instagram: /knowledgegate.edu2026
TikTok: .edu

14/03/2026

🎯 **At What Angle Does Range = Maximum Height? | Projectile Motion**

Do you know the launch angle at which the **range of a projectile becomes equal to its maximum height?** 🤔

Using projectile motion formulas and solving **R = H**, we get:

**tanθ = 4**

So the required angle is approximately **76°** 🚀

📚 Class XI Physics – Projectile Motion
Clear concepts with **Knowledge Gate Academy**.

▶ Watch the short lecture here:
https://youtube.com/shorts/EJSnHVOV2e4?feature=share

YouTube:
Instagram: /knowledgegate.edu2026
TikTok: .edu

At what angle does the **Range of a Projectile become equal to its Maximum Height?** 🤔Using projectile motion formulas, we solve **R = H** and get:**tanθ = ...