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LITERATURE ANSWERS
PROSE-ANSWERS
(You Are To Answer Only Two(2) Only.
(5)
As her name suggests, Mary Rambo is both Mary, the saintly mother of Jesus, and Aunt Jemima, the female version of Sambo. Mary is a strong black woman who has learned to survive the violence and corruption of the city by relying on her inner resources. A Southern woman who now lives in the North, Mary provides the narrator's only source of love and comfort. After his harrowing experience at the Liberty Paint Factory Hospital, the narrator is grateful for Mary's kindness and generosity. Seeing him simply as a fellow human being who needs help, Mary takes him into her home, cooks for him, and nurses him back to health. When he can't pay his rent, she tells him not to worry. Seeing how depressed he is about his situation, Mary encourages him and reassures him that he will make something of himself and be "a credit to his race." She does everything she can to demonstrate her faith in him and, in effect, adopts him as her surrogate son. During this time, the narrator sees Mary as the saintly mother figure, referring to her as his anchor and guide, and appreciating her support and generosity. But after he meets Brother Jack and begins to work for the Brotherhood, he sees Mary through different eyes. She becomes a source of shame and embarrassment for him, prompting him to try to shatter her image, as symbolized by his futile attempt to discard the cast-iron bank. The bank, like Mary, represents a part of his heritage he wants to forget. Although he initially appreciates her cooking, he now complains of his steady diet of cabbage. At first he sees her home as a sanctuary and source of solace and comfort, but later he notices the noise, poverty, and filth surrounding her, as indicated by the banging on the pipes, the smell of cabbage, and the invasion of roaches. He finally leaves Mary without even saying goodbye, confident that she will survive, having undoub

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PHYSICS ESSAY
(1)
Workdone = 1/2Fe
= 1/2 × 40 × 1/100
= 1/5 = 0.2J
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(2a)
(i)Navigation satellites e.g global position system - GPS
(ii) Communication satellites eg ANIK

(2b)
V = 2πR/T
For every second,
Speed, V = 2πR
V = 2 × 22/7 × 6300
V = 39,600km/s
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(3)
V=u cosθ -gt
V=40*cos30-10*1
V=34.64-10
V=24.64m/s
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(5a)
Wave particles duality is the concept in quantum mechanics that every particles or quantum entitle may be described as either a particle or wave.

(5b)
λ=h/MV
4.2*10^-¹¹=h/1.6*10^-²³
h=4.2*10^-¹¹ * 1.6*10^-²³
h=6.72*10^-³⁴
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(6)
(i)reflection
(ii)refraction
(iii)diffraction
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(7a)
Fiber optics work on the principle of total internal reflection.

(7bi)
Core: This is the light transmission area of the fiber, either glass or plastic.

(7bii)
cladding is made of a material with a slightly lower index of refraction than the core
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(8ai)
Hooke's law states that the extension e produced by an elastic material is directly proportional to the applied force provided the elastic unit is not exceeded.

(8aii)
(i) Given extension, e = I2 - I1 = 0.75 - 0.20 = 0.55m
Force applied, Fe = (1.95 - 0.30) × 10
= 1.65 × 10 = 16.5N
Force constant , K = F/R = 16.5/0.55 = 30N/m

(ii) Using F = K (I1 - Io)
m1g = K ( I1 - Io)
= 0.30 × 10 = 30(0.20 - Io)
= 0.10 = 0.20 - Io
Io = 0.20 - 0.10
Io = 0.10m
Length of spring when it was unloaded = 0.10m

(8bi)
Diffusion is the net movement of particles from a region of higher concentration to a region of lower concentration.

(8bii)
(

PHYSICS-OBJ

1-10:AAABACCDDB

11-20:ACCDCBCBAC

21-30:CCCBBDDBBB

31-40:ACBBCCCAAD

41-50:BBADCCBAAC

Complete

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QUESTION 1

Number 1biii corrected and now authentic. NO.1biii corrected use this.

(1a)
Volume of burrete = 50.00cm³
Volume of pipette = 25.00cm³
Indicator = Methyl orange

TABULATE

Final burette readings (cm³); 37.50 | 22.50 | 37.50 | 44.50

Initial burette readings(cm³); 0.00 | 0.00 | 0.00 | 0.00

Volume f Acid used (cm³); 37.50 | 22.50 | 22.50 | 22.50

Volume of A used = 1st + 2nd + 3rd/3
= 22.50+22.50+22.50/3
Average volume of A used = 22.50cm³

(1bi)
Concentration of A ( CA )?
2.03g in 500cm³ of solution

Volume = 500cm³/1000 = 0.500dm³
In g/dm³ = 2.03/0.5 = 4.06g/dm³

To find concentration in mol/dm³
Conc. of A in mol/dm³ = Conc. of A in g/dm³/Molar mass

Conc. of A in mol/dm³ = 4.06/36.5
= 0.1112mol/dm³
Molar mass of A (HCL) = 1+35.5 = 36.5g/mol

(1bii)
Number of mole of the Acid in average titre
Na = CaVa
= 0.1112 × 22.50
= 2.52moles

(1biii)
Nb= ? Na= 3, Ca= 0.1112mol/dm³, Cb = 0.12mol/dm³ , Va = 22.50cm³, Vb = 25.00cm³

CaVa/CbVb= nA/nB

0.1112×22.50/0.12×25 = 3/nB

nB × 2.502 = 9
nB = 9/2.502 =
nB = 3.597moles

(1biv)
Mole ratio of Acid to base
nA:nB
= 3:3
= 1:1


======================================================
QUESTION 2

(2a)
Test; C + 10cm³ of distilled water + filter

Observation; C dissolves partially to give a light green solution. Blue filtrate and green residue

Inference; C is a mixture of soluble and insoluble salt

(2bi)
Test; 2cm³ of filtrate + NaOH in drops in excess

Observation; Blue precipitate remains

Inference; CU²+ is present

(2bii)
Test; 2bi + warm

Observation; a colourless gas with a chocking smell which turns moist red litmus blue and forms dense white fumes with hydrogen chloride gas

Inference; NH³ from NH⁴+

(2biii)
Test; 2cm³ of filtrate + BaCl² + excess HCl

Observation; white precipitate, precipitate Remains

Inference; SO²- CO3²- or SO4²- is present, SO4²- confirmed

(2ci)
Test; Residue + HNOg

Observations; effervescence of a colourless and odourless gas which turns like water milky and turns mo