29/01/2022
Electricity Class X CH 8.
Why is electricity considered as the most convenient form of energy? 1m HSLC ’18.
Ans:- Because it can be manipulated to our requirements much better than any other source of energy.
What is electric charge? What is its SI units? 2m
Ans:- The electric charge is a fundamental physical quantity of matter due to which electric phenomena are produced in the matter.
The SI unit of electric charge is coulomb (C ).
What is meant by electric current? What is its SI units? 2m
Ans:- The continuous flow of electric charges through a conductor constitutes an electric current. Or, The rate of flow of electric charges through a cross section of a conductor per unit time.
The SI unit of electric current is ampere (A ).
What is meant by electric circuit?
Ans:- A closed path of a continuous flow of electric current is called an electric circuit.
What is the conventional direction of electric current?
Ans:- The conventional direction of electric current is from positive terminal of a cell or a battery to the negative terminal through the outer circuit.
However, the actual direction of electron flows is from negative terminal to the positive terminal which is opposite to the direction of conventional current.
Expression of electric current: If a net ‘Q’ flows across any cross section of a conductor, perpendicular to the direction of current ‘I’ flow in time ‘t’ then the current through the cross section is I = Q/t
Define one ampere of current.
Ans:- One ampere of electric current is constituted by the flow of one coulomb of charge per second, that is given by 1A = 1C/1s
NB: 1 electron = 1.6 × 10-19 C, 1C = 6 × 1018 electrons.
Define one coulomb of electric charge.
Ans:- 1C of electric charge is the amount of charge conveyed by 1 Ampere in 1 Second. Q = It or 1C = 1A × 1s.
Name a device/instrument that is used to measure electric current in a circuit. How is it connected in an electrical circuit?
Ans:- Ammeter.
NB: Smaller quantities of current are expressed in milliampere, microampere or in nanoampere.
1 milliampere (1mA)= 10-3 A
1 microampere (1μA) = 10-6 A
1 nanoampere (1nA) = 10-9 A
Ammeter is always connected in series in an electrical circuit.
A current of 0.4 A is made to pass through an electric circuit for 15 minutes. Find the amount of electric charge that flows through the circuit.
Ans:- Given, I = 0.4 A; t = 15min = 15 × 60 sec
We have, Q = It
= 0.4 A × (15 × 60)sec = 4 × 15 × 6 As = 360C.
Calculate the number of electrons in 4.8 C of electric charge.
Ans:- Total Charge (Q) = No. of electrons × Charge of an electron
Therefore No. of electrons = (Total charge (Q))/(Charge of an electron)
1 electron = 1.6 × 10-19 C
Therefore, No. of electron = (4.8)/(1.6×10¯19)
= 3 × 1019 electrons
Electric potential and potential Difference
What is meant by electric potential?
Ans:- The electric potential is a physical quantity which determines the flow of electric charges from one point to another irrespective of the path followed.
What is meant by electric potential difference? What is its SI unit? HSLC ’11.
Ans:- The potential difference between the two points in an electric circuit carrying current is the amount of work done to move a unit charge from one point to the other.
Thus, potential difference, V between two points = (work done(W))/(Charge (Q) )
The SI unit of potential difference is Volt (V)
Define 1 Volt. 1m HSLC 2017
Ans:- 1 Volt is the electric potential difference between the two points in a current carrying conductor when 1 joule of work is to be done to move one coulomb of charge from one point to another.
Potential difference, V = (work done(W))/(Charge (Q) )
i. e 1 Volt = (1 joule)/1coulomb
i. e 1V = 1J/1C = 1JC—1
What is a voltmeter? How is it connected in electrical circuit?
Ans:- The voltmeter is an instrument used for measuring electrical potential difference.
The voltmeter is always connected in parallel across the points whose potential difference is to be measured.
Try to answer : Book Page 148.
What is the device that can maintain a potential difference across a conductor?
Ans:- A battery connected across two points of a conductor can maintain a potential difference between the two points.
What is meant by saying that the potential difference between the two points is 1 Volt?
Ans:- The meaning is that when 1 joule of electrical work is done by the flow of 1 coulomb of electric charge from one point to the other, the potential difference that exists between the two points is 1 Volt.
How much energy is given to 2 coulomb of charge passing through a cell of 1.5V?
What constitutes electric current in a conductor?
Ans:- The motion of electrons through a conductor constitute electric current in the conductor.
State Ohm’s Law. (Current – voltage relationship)
Ans:- Ohm’s Law states that at a constant temperature, the current flowing through a conductor is directly proportional to the potential difference across its ends.
EXPRESSION OF OHM’S LAW:
If ‘I’ is the current flowing through a conductor and ‘V’ is the potential difference (or voltage) across its ends.
Then, V ∝ I
Or V/I = a constant (R)
Or V = IR
Define 1 Ohm ( Ω ).
Ans:- 1 Ohm ( Ω ) is the electrical resistance of a conductor which allows a current of 1 ampere to flow through the conductor when there is a potential difference of 1 Volt across the ends of the conductor.
Thus, 1 Ω = 1V/1A
What is a rheostat?
Ans:- A component or a device generally used to regulate the quantity of current in the circuit without changing the voltage of the source is called a rheostat.
Thus, it is used to change the resistance in the circuit.
RESISTANCE OF CONDUCTORS:
What is meant by electrical resistance of a conductor? What is its SI unit?
Ans:- The inherent property of a conductor to resist the flow of charges through it is called resistance.
The SI Unit of resistance is Ohm ( Ω ).
On what factors does resistance depend.
Or, What are the factors on which the resistance of a metallic character depends? - 3m (2m HSLC 2013)
Ans:- The factors on which the resistance of a metallic character depends on are-
Length of the conductor i.e R ∝ l
Cross section area i.e R ∝ 1/A
Nature of the material
Temperature of the conductor.
Obtain the relation of electrical resistivity of a conductor. 3m (HSLC 2015)
Ans:- We have, R ∝ l and R ∝ 1/A
Combining these two factors we get,
R ∝ l/A
R = ρ l/A
Thus, ρ = RA/l , Where ρ = Resistivity of the conductor.
A 1.0m long wire has 1mm diameter and resistance of 7Ω. Calculate the resistivity of the material. - 2m (HSLC 2017)
Ans:- Here, l = 1.0m, d = 1mm = 1 × 10-3 m, R = 7 Ω
Thus, ρ = RA/l
ρ = (Rπd^2)/4l
ρ = (7× 22 (1 × 10¯^3 )^2)/(4×7 ×1)
ρ = 11/2 × 10-6
ρ = 5.5 × 10-6 Ωm
The resistance of a wire is 50Ω at 20°C. If the length and diameter of the wire are 1m and 5 × 10-4 m respectively, calculate the resistivity of the material of the wire. (Example 8.6)
Ans:-
COMBINATION OF RESISTANCES (OR RESISTORS)
There are two methods of joining two or more resistors. (i) Series Combination and (ii) Parallel Combination.
Derive an expression for the resultant resistance of a number of resistance connected in series.
Ans:- Let the resistances R1, R2 and R3 be connected end-to-end in series.
The same current (I) flows through all resistors.
The potential difference V1, V2and V3 across the resistances R1, R2 and R3 are given by V1 = IR1, V2 = IR2 and V3 = IR3
The potential difference (V) across the series combination is equal to the sum of the potential difference across the individual resistances.
V = V1 + V2 + V3.
The resistances connected in series may be replaced by a single resistance (Rs), having a potential difference V across its ends, while a current I flows through it, so that V = IRs
Hence, V = V1 + V2 + V3.
IRs = IR1 + IR2 + IR3
IRs = I(R1 + R2 + R3)
Rs = R1 + R2 + R3, which is the required expression.
Thus, the resultant resistance is equal to the sum of the individual resistances and is greater than the greatest of the individuals.
Derive an expression for the resultant resistance of a number of resistance connected in parallel.
Ans:- Let the resistances R1, R2 and R3 be connected in parallel with one each of their terminals joined together at a point and the other terminals joined together at another point.
The potential difference (V) across all the resistances is the same, while the current are different.
Thus the currents I1, I2, and I3 across the resistance R1, R2 and R3 are respectively given by
I1 = V/R1, I2 = V/R2 and I3 = V/R3
The total current in the circuit is equal to the sum of the individual currents.
I = I1+ I2 + I3
The resistances connected in parallel may be replaced by a single resistance (Rp), having a potential difference V across its ends, while a current I flows through it, so that
I = V/RP
I = I1+ I2 + I3
V/RP = V/R1 + V/R2 + V/R3
V/RP = V(1/R1 + 1/R2 + 1/R3)
1/RP = 1/R1 + 1/R2 + 1/R3, which is the required expression.
Thus, the reciprocal of the resultant resistance is equal to the sum of the reciprocals of the individual resistances. The result is lesser than the least of the individuals.
LAWS OF COMBINATION OF RESISTANCES
Series combination:
The combined resistance of any number of resistors connected in series is equal to the sum of the individual resistances. i. e Rs = R1 + R2 + R3
The same current flows through all resistors irrespective of the value of resistance.
The potential difference across each individual resistor is directly proportional to the resistance.
Parallel Combination:
The reciprocal of the combined resistance of any number of resistors connected in parallel is equal to the sum of the reciprocal of all the resistances.
The potential difference across each individual resistor remains same, irrespective of the values of the resistance.
The current flowing through each of the resistors is inversely proportional to the value of resistance.
HOW ARE THE HOUSEHOLD ELECTRIC APPLIANCES/COMPONENTS CONNECTED TO THE MAIN SUPPLY:
What are the disadvantages of series connection of Household Electric Appliances with the main supply?
Ans:- The disadvantages of series connection of Household Electric Appliances with the main supply are as follows:-
(i) In series connection, the same current flows through all appliances. But, the appliances may need currents of widely different values for operation. Hence operation of all appliances may not be practicable.
(ii) The resultant resistance increases in series connection with the increasing number of appliances. Hence, the current may be much reduced insufficient for operation of same or all of the appliances.
(iii) When one of the components gets fused, the circuit is broken and none of the components will work further.
(iv) It is troublesome to check the wrong thing wherever it is there in the connecting system. Hence series arrangement of electrical components is not used for domestic circuit.
What are the advantages of parallel connection of Household Electrical Appliances with the Mains supply?
[Or, Why is Household electrical wiring done in parallel circuits.]
Ans: (i) In parallel connection, the current from the Mains supply is divided in accordance with the current carrying capacity of the individual components. Hence operation of all appliances is practicable.
The resultant resistance decreases in parallel connection with the increasing number of appliances. Hence the current may be increased and divided among the components for operation.
When one of the components gets fused or fails, the other components are not affected.
All the appliances operate with the same voltage. Hence interchange of the appliances with need in position is practicable.
Why parallel connection is preferred in household circuits? - 2m (HSLC 2011)
Ans:- # It can minimize the equivalent resistance
# All the appliances get the same voltage.
# When are appliances gets fused or fails the other appliances will continue to work.
HEATING EFFECT OF ELECTRIC CURRENT
How is heating effect of electric current produced ?
Ans: When an electric appliance is fitted with a power source, some of the electrical energy of the source is expended in doing useful work of the appliance. The remaining part of the electrical energy, by the law of transformation of energy is transformed into the heat energy. As a result, the appliance gets heated up. Thus, heating effect of electric current is produced.
State Joule's law of heating effect of electric current.
Ans: The heat (H) produced in a resistor is directly proportional to
(i) the square of the current (I²) passing through the resistor, when the resistance (R) of the resistor is constant i.e. H ∝ I², when R is constant
(ii) the resistance (R), when the current (I) is constant i.e. H ∝ R, when I is constant
(iii) the time (t) for which the current flows through the resistors, when both R and I are constant i. e H ∝ t, when both R and I are constant.
Thus, we have, H = I²Rt, which is known as Joule’s law of heating effect of electric current.
Prove Joules Law of Heating effect mathematically.
Or, Show that the amount of heat energy produced on an electrical conductor is directly proportional to the resistance and to the square of the current flowing through it. (3m 2001)
Ans:- When the current (I) flows through a resistor of resistance R for time t in potential difference V expending charge Q then,
Amount of work done(W) in the form of Heat energy (H) = VQ
H = IRIt [since v = IR and Q = It]
H = I²Rt.
APPLICATION OF HEATING EFFECT OF ELECTRIC CURRENT
How is heating effect of electric current utilised in household electrical appliances? Give some examples.
Ans: When an electrical appliance having a high resistance is in an electrical circuit, much heat is evolved in the heating element of the appliance. The connecting wires are of very low resistance. Hence negligible heat is produced in the connecting wires. As a result, the heating element of the appliance glows while the connecting wires do not glow.
Example :
Electric Bulb: The filament of an electric bulb is made of a material of high resistance such as tungsten. At the same time, the filament is of very small cross-section (fine) and appreciable length. Thus, when an electric current flows through the filament, much heat is evolved. A large part of the power consumed by the filament appears as heat while a smaller part of it is in the form of light radiation.
Other appliances: The heating effect of electric current (Joule heating effect) is also utilised in many useful household electrical appliances such as electric iron, electric cooker, electric kettle, electric heater, etc.
What is electric safety fuse ? Describe its construction and principle of action.
Ans: The electric safety fuse is a device to produce a cut in the electric circuit when there is overloading in the circuit so as to save things from electric damage.
Construction : The fuse wire is made of a metal or alloy of low melting and of high electrical resistivity. It is generally made of an alloy of tin and copper. The thickness and length of the fuse wire depend upon the maximum current permissible for the circuit. It is normally encased in a cartridge of porcelain with metal ends. There is a marking of rated maximum current to be put in use.
Principle of action : The fuse wire is connected in series with the live-line of the electric mains. When there is overloading in the electric circuit, the fuse wire gets heated up to such an extent that it melts and breaks the circuit. Thus, consuming stations are saved from electric damage.
ELECTRICAL POWER, WORK AND ENERGY :
Define Electric Power.
Ans: The rate of dissipation or consumption of electrical energy is called electric power.
Electric Power (P) = (Electric energy )/time
P = (V× Q)/t
P = (V× I× t)/t
P = V × I
P = IR × I
P = I²R
P = (V/R)² × R
P = V²/R
What is the SI unit of electric Power ? Define it.
Ans: The SI unit of electric power is watt (W).
1 watt is the rate of dissipation or consumption of 1 joule of electric energy. 1W = 1J/S, Or, 1J = 1W x 1S.
[1 watt may also be defined as the power consumed by a device when operated with a current of 1 ampere under a potential difference of 1 volt.
1W = 1 V × 1A
Define watt hour.
Ans: The electric energy consumed when 1watt of power is used for 1 hour, is called watt hour (Wh).
It is the unit of electrical energy.
What is the commercial unit of electrical energy? Define it.
[Or, Define one unit of electrical energy]
Ans: The commercial unit of electrical energy is called kilowatt hour (KWh).
The electric energy consumed when 1 kilowatt of power is used for 1 hour, is called kilowatt hour (KWh).
The KWh = 1000 watt x 1 hour
= 1000 watt x (60 x 60) second
= 3.6 x 10^6 watt-second
= 3.6 x 10^6 joule (J).
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