My-Communication Academy International

19/08/2026

A single contaminated connector is all it takes to bring your signal down 🔌
A microscopic scratch or a fingerprint on a connector's end-face is enough to spike Insertion Loss and take down the whole network — before you even start troubleshooting.
What's inside the guide:
We've broken down everything you need to know about cleaning and inspecting optical connectors in the Telecom Engineer's Guide: How contaminants impact signal quality (Insertion Loss / Return Loss) The right tools for inspection and cleaning (inspection microscope, cleaning pens, wipes) Step-by-step dry and wet cleaning procedures The IEC 61300-3-35 standard and how it defines connector quality
Get your free copy 🎁
Comment "GUIDE" below, and we'll send it straight to your DM 📩

18/08/2026

When are "3 Sectors" no longer enough? 📶

Does every increase in *Traffic* mean we need *6 Sectors*? Let's break down the concept simply in this post.

18/08/2026

How do we calculate the required height for a telecommunications tower? 📡

When designing a microwave link between two locations, ensuring line-of-sight (LOS) between antennas alone is not enough.

Selecting the appropriate tower and antenna height depends on several engineering factors, most notably:

* **Line of Sight (LOS)**
* **Fresnel Zone**
* **Earth Bulge**
* **Obstacle and Terrain Heights**
* **k-factor**
* **Diffraction Loss**
* **Link Availability Requirements**

Consider a hypothetical **30 km** microwave link operating at **7 GHz**, with an obstacle located at the midpoint reaching a height of **80 meters** relative to the vertical datum used in this example.

---

1. Is Line-of-Sight (LOS) Alone Sufficient?

Not necessarily.

In a microwave link, electromagnetic waves do not travel merely as a razor-thin line. Instead, they occupy an elliptical volume around the propagation path known as the **Fresnel Zone**.

Consequently, even if a clear geometric LOS exists between antennas, an obstacle positioned near the propagation path can degrade the signal due to **diffraction** and **interference**.

Therefore, rather than simply asking:

"Can I visually see the other end?"

We must ask:

"Is there adequate clearance for the propagation path and the Fresnel zone?"

A common guideline in link design uses *60% of the first Fresnel zone radius* as the required clearance. However, actual clearance requirements depend on the specific design methodology, path characteristics, the effective Earth radius factor ($k$-factor), and target link availability.

---

2. Calculating the Fresnel Zone

For an obstacle located at the midpoint of a $30\text{ km}$ link:
Total distance ($D$):$30\text{ km}$
* **Distance from Site A to obstacle ($d_1$):** $15\text{ km}$
* **Distance from obstacle to Site B ($d_2$):** $15\text{ km}$
* **Frequency ($f$):** $7\text{ GHz}$

Using the formula for the first Fresnel zone radius ($r_1$):

$$r_1 = 17.32 \times \sqrt{\frac{d_1 \times d_2}{f \times D}}$$

Substituting the values:

$$r_1 = 17.32 \times \sqrt{\frac{15 \times 15}{7 \times 30}} \approx 17.9\text{ meters}$$

Thus, the first Fresnel zone radius at the midpoint of this link is approximately **$17.9\text{ meters}$**.

To calculate a **60% clearance**:

$$0.6 \times 17.9 \approx 10.7\text{ meters}$$

Under this educational assumption, an additional clearance of roughly **$10.7\text{ meters}$** above the obstacle is required before accounting for Earth curvature.

---
3. Earth Curvature Effect (Earth Bulge) 🌍

Over long distances, the Earth's surface cannot be treated as a flat plane.

Due to Earth curvature, the surface appears to bulge upward toward the midpoint of the link path. This effect is known as **Earth Bulge**.

The magnitude of Earth bulge depends on the path distance and the **Effective Earth Radius Factor ($k$-factor)**.

Assuming a standard value of $k = \frac{4}{3}$, the Earth bulge at the midpoint of a $30\text{ km}$ link is approximately:

$$\text{Earth Bulge} \approx 13.2\text{ meters}$$

> [!NOTE]
> The $k$-factor is not a fixed constant across all locations and atmospheric conditions; it varies with atmospheric refraction phenomena.

---

4. Aggregating Clearance Factors

Combining the factors from this example:

* **Obstacle Height:** $80\text{ m}$
* **Earth Bulge:** $\approx 13.2\text{ m}$
* **60% Fresnel Clearance:** $\approx 10.7\text{ m}$

Total required clearance height at the obstacle location:

$$80 + 13.2 + 10.7 = 103.9\text{ m} \approx 104\text{ meters}$$

This value represents the required elevation for the **propagation path** at the obstacle location relative to the reference datum.

⚠️ **However, this does NOT mean the tower height itself must be 104 meters.**

This is a critical distinction in link engineering.

---

# # # 5. Does This Mean the Tower Must Be 104 Meters High?

**No.**

In actual link design, tower height cannot be determined simply by summing:

$$\text{Obstacle Height} + \text{Earth Bulge} + \text{Fresnel Clearance}$$

A comprehensive path analysis is required. Key inputs include:

* Ground elevation at both endpoints
* Obstacle heights and exact locations along the path
* Distance from each obstacle to both endpoints
* Antenna heights above ground level (AGL)
* Operating frequency
* Applicable $k$-factor value(s)
* Fresnel clearance requirements
* Terrain elevation profile
* Target link availability
* Required fade margin

Engineers conduct a **Path Profile / Clearance Analysis** using these variables to determine the optimal antenna centerline and tower structural heights.

---

# # # 6. What If the Obstacle Is Off-Center?

In our example, the obstacle was located at the midpoint, making $d_1 = d_2 = 15\text{ km}$.

If an obstacle lies closer to one end of the link ($d_1 \neq d_2$), the Fresnel zone radius changes accordingly. Therefore, the midpoint radius of $17.9\text{ m}$ cannot be applied universally across the path; $r_1$ must be recalculated at each specific obstacle location.

---

# # # 7. What Happens If an Obstacle Encroaches on the Fresnel Zone?

When an obstacle enters or obstructs the Fresnel zone, **diffraction** occurs around the edge of the obstacle, introducing additional **diffraction loss**.

As the obstruction deepens into the propagation path, path attenuation increases significantly. This reduces received signal level (RSL) and can degrade overall **link availability** if sufficient fade margin was not factored into the link budget.

---

Summary 📡

Determining the required tower or antenna height is far more complex than just adding a couple of meters to an obstacle's height. It requires rigorous engineering analysis considering:

$$\text{LOS} + \text{Fresnel Zone} + \text{Earth Bulge} + \text{Diffraction} + \text{Terrain Profile} + k\text{-factor} + \text{Link Availability}$$

In our simplified educational model ($D = 30\text{ km}$, $f = 7\text{ GHz}$, Obstacle $= 80\text{ m}$, $k = 4/3$):

* **Fresnel Radius ($r_1$):** $\approx 17.9\text{ m}$
* **60% Fresnel Clearance:** $\approx 10.7\text{ m}$
* **Earth Bulge:** $\approx 13.2\text{ m}$
* **Required Path Elevation at Obstacle:** $\approx 104\text{ m}$

> **Key Takeaway:** $104\text{ meters} \neq \text{Tower Height}$. The actual structural height of towers and antennas can only be finalized after conducting a full **Path Profile**, **Clearance Analysis**, and **Link Budget** using real site terrain and obstruction data.

---

💬 Discussion Question:

In your opinion, which factor plays the most critical role when determining microwave tower heights: Fresnel Zone, Earth Bulge, or Terrain Profile? Why? 👇📡

13/08/2026

In traditional systems, antennas broadcast signals across an entire sector, consuming significant power and causing interference for all users in the area. With the advent of **Beamforming in 5G**, the engineering approach has fundamentally changed. Instead of broadcasting indiscriminately, **Massive MIMO** antenna arrays are used to form a narrow, focused beam that follows the user wherever they move.

This technology relies on controlling the **phase** of signals emitted from multiple small antennas, creating **constructive interference** in the direction of the target user and **destructive interference** in all other directions. This not only enhances the received signal strength but also dramatically increases network capacity by reducing noise and interference in adjacent channels.

To understand how this concept integrates with the rest of the network architecture, our **Integrated Telecommunications Engineering Course** covers 5G details and its supporting technologies—such as **Millimeter Waves** and **Massive MIMO**—complete with practical explanations on system design and deployment.

📩 Do you think Beamforming will eliminate the need to increase cell towers in high-density areas?

12/08/2026

My-Communication Academy presents the Optical Fiber Course for those who understand that network stability relies on a precise grasp of physical phenomena and components that ensure high-speed data transmission without signal loss.

🔹 What will you learn in the Optical Fiber Course?

* Basics, structure, and components of optical fibers
* Technical differences between Single-Mode Fiber (SMF) and Multi-Mode Fiber (MMF)
* Characteristics of the spectral windows: 850 nm, 1310 nm, and 1550 nm
* Applications of dispersion-modified fibers in modern networks
* Uses of bend-insensitive fibers in tight spaces
* Operating mechanisms of LED and Laser light sources
* Functions of PIN and APD optical detectors in signal conversion
* Signal multiplexing and demultiplexing techniques using MUX and DEMUX

📩 Which do you prefer to use in short-range Local Area Networks (LANs), SMF or MMF, and why?
https://my-communication.uk/

11/08/2026

11/08/2026

🔋 **How does a telecom engineer size the appropriate battery for a telecom tower?**

What happens when the power cuts out at a telecom site?

Can you just pick any battery and run the site for several hours?

**The answer: No.**

Selecting a battery depends on a set of engineering calculations starting from the site load and ending with determining the required backup capacity.

Let’s look at a practical example 👇

🔹 **Total site load = 2,300 Watts**

Hypothetically distributed as follows:

▪️ **4G Equipment:** 1,200 W

▪️ **Cooling System:** 800 W

▪️ **Transmission Equipment:** 200 W

▪️ **Lighting & Auxiliary Loads:** 100 W

Therefore:

**Total Load = 2,300 W**

⚡ **How much energy do we need to operate the site for 8 hours?**

Simply put:

$$\text{Required Energy} = \text{Load} \times \text{Operating Time}$$

$$2,300 \times 8 = 18,400 \text{ Wh}$$

Meaning the site theoretically requires about:

**18.4 kWh**

🔋 **How do we convert this energy into battery capacity?**

Let's assume the site operates on a **-48V DC** power system.

**Theoretical Capacity:**

$$18,400 \div 48 \approx 383 \text{ Ah}$$

But does this mean a 383 Ah battery will be sufficient?

**Not necessarily.**

Actual design must account for several critical factors:

▪️ **Depth of Discharge (DoD)**

▪️ **Power System Efficiency**

▪️ **Safety Margin**

▪️ **Operating Temperature**

▪️ **Battery Aging**

▪️ **Discharge Curves and Manufacturer Specifications**

For example, if we assume:

* **DoD** = 80%
* **System Efficiency** = 90%
* **Safety Margin** = 20% (+1.2 factor)

Then the approximate calculated capacity becomes:

$$383 \div 0.8 \div 0.9 \times 1.2 \approx 639 \text{ Ah}$$

Consequently, we might need a battery bank with a nominal capacity close to **700 Ah at -48V**. However, the final selection isn't made by this number alone—it requires reviewing the battery datasheet, discharge curves, and actual operating conditions.

💡 **Here lies the importance of engineering design.**

Choosing a battery isn't just about picking a large Ah number; it is the result of analyzing:

**Load → Backup Duration → Voltage → System Efficiency → DoD → Operating Conditions → Battery Lifespan.**

**The simple rule:**

📈 As the load or the required backup duration increases, the required battery capacity increases.

**Which do you think has a greater impact on battery size: increasing the load or increasing the backup duration?** 👇

10/08/2026

https://my-communication.uk/
📡 Two sites 12 km apart… and a required capacity of 1 Gbps. Which would you choose: Fiber or Microwave?

It sounds like a simple question, but in telecom engineering, there is no single technology that is always the best.

The best technology is the one that meets the project requirements with the optimal balance between performance, feasibility, time, and cost.

Let’s assume we have a project with the following specifications:

🔹 **Direct Line-of-Sight Distance:** 12 km

🔹 **Required Capacity:** 1 Gbps

🔹 **Line of Sight (LOS):** Available with proper Fresnel Zone Clearance

🔹 **Actual Fiber Route Distance (to nearest point):** 18 km

🔹 **Project Deployment Deadline:** 30 days

Which option would be more suitable?

---

📡 **First: Microwave**

Having a clear LOS makes a Microwave link a logical choice to analyze.

Let’s assume we use an 11 GHz frequency over a distance of 12 km.

The Free Space Path Loss (FSPL) can be calculated using:

$$FSPL = 92.45 + 20 \log_{10}(f) + 20 \log_{10}(d)$$

Where:

* $f = 11\text{ GHz}$
* $d = 12\text{ km}$

By substitution:

$$FSPL = 92.45 + 20.83 + 21.58$$

$$FSPL \approx 134.9\text{ dB}$$

⚠️ **However, here is an important engineering detail:**

This value alone does not determine whether the link will succeed or fail.

A successful Microwave link requires a full **Link Budget** calculation, considering factors such as:

🔹 Transmit Power

🔹 Antenna Gain

🔹 Feeder/System Losses

🔹 Receiver Sensitivity

🔹 Fade Margin

🔹 Required Availability

🔹 Interference

🔹 Atmospheric & Rain Attenuation

🔹 Channel Bandwidth & Modulation

It is also essential to ensure adequate Fresnel Zone clearance along the path.

Depending on the equipment, frequency, channel bandwidth, and available spectrum, a link can be designed to deliver 1 Gbps if the Link Budget and Availability requirements permit.

✅ **Initial Conclusion:**

Microwave is an engineerable and viable option in this scenario, provided the actual link design is verified.

---

🔌 **Second: Fiber**

Now, let’s consider the Fiber Optic option.

The direct distance between the sites is 12 km, but let's assume the actual required route to reach the nearest Fiber connection point is 18 km.

For simplicity, let's assume an attenuation coefficient of:

**0.35 dB/km**

Therefore:

$$\text{Fiber Loss} = 18 \times 0.35 = 6.3\text{ dB}$$

Then, assuming:
🔹 8 Splices × 0.1 dB = 0.8 dB

🔹 2 Connectors × 0.5 dB = 1.0 dB

Consequently:

$$\text{Total Calculated Loss} = 6.3 + 0.8 + 1.0 = 8.1\text{ dB}$$

⚠️ **Does this automatically mean the Fiber link will work?**

Not necessarily.

The total loss must be evaluated against the **Optical Power Budget** of the selected optics, taking into account:

🔹 Transmit Power

🔹 Receiver Sensitivity

🔹 Splice & Connector Losses

🔹 Fiber Attenuation

🔹 Design/Safety Margin

🔹 Speed and actual distance requirements

Thus, **8.1 dB** is simply the calculated loss based on these assumptions, not a final proof of a successful Fiber link.

✅ **Initial Conclusion:**

Fiber is also technically feasible, but must be confirmed via an Optical Power Budget and actual route design.

---

🤔 **So, where lies the decision?**

If both Microwave and Fiber can theoretically deliver the required capacity, why choose one over the other?

This is where true engineering thinking begins.

---

⚖️ **Comparing the Options**

📡 **Microwave**

* ✔ Direct distance: 12 km
* ✔ Leverages clear Line of Sight (LOS)
* ✔ No new Fiber path construction required
* ✔ Faster to deploy if sites, permits, and equipment are ready
* ✔ Potentially more cost-effective (CAPEX) in this scenario
* ✔ Ideal when time is a critical factor

🔌 **Fiber**

* ✔ Extremely high capacity scalability
* ✔ Independent of Line of Sight
* ✔ Provides a robust foundation for future expansion
* ✔ Requires an 18 km physical route in this scenario
* ✔ May require civil works, permits, and field construction
* ✔ Higher cost and longer deployment time when building a new route

---

⏱️ **What about the 30-day deadline?**

**Time to Deploy** becomes a decisive factor here.

If completing the project within 30 days is a hard requirement, and building a new 18 km Fiber route requires civil works, rights-of-way, and permits, whereas a Microwave link can be commissioned within the deadline, Microwave becomes significantly more attractive.

However, the final decision is not based on time alone.

We must evaluate: **Performance + Feasibility + Availability + Time + Cost**.

---

🏆 **Initial Recommendation**

Based on the given data and assumptions:

📡 **Microwave is the preferred choice for this scenario.**

Not because Fiber is a weaker technology.

Nor because Microwave is always better.

Rather, because Microwave meets the project requirements while offering a better fit for current operational constraints:

**12 km + 1 Gbps + Clear LOS + 30 Days + No need to build an entire 18 km Fiber route from scratch.**

*(Assuming the Link Budget, Fade Margin, Availability, Interference, and spectrum allocation allow for the required design).*

---

💡 **A fundamental rule in Telecom Engineering:**

> *"Don't choose the strongest technology… choose the most suitable technology for the project requirements."*

An engineer doesn't look at Capacity alone; they balance:

**Performance + Feasibility + Time + Cost**

This is precisely the mindset required when tackling technical interviews and real-world Telecom Transmission & Backhaul projects.

---

📌 **Now it’s your turn:**

If you were the Lead Engineer on this project, would you choose **Microwave** or **Fiber**?

And why?

Share your choice in the comments below, along with the most critical factor behind your decision! 👇

10/08/2026

Which antenna do you choose when the connection is between only two points? 📡

Choosing the right antenna in Wireless Point-to-Point projects makes a huge difference in network performance.

Leave a comment with the word "INTERESTED" to receive the Wireless course details! 💬👇
https://my-communication.uk/

09/08/2026

Do you believe that all wireless network issues start with a clear, full service outage? 📡

In the world of RF Networks, some problems do not manifest immediately as a major outage. Instead, they begin with a subtle indicator signaling a flaw in system health.

One of the most critical indicators is **VSWR (Voltage Standing Wave Ratio)**.

A VSWR alarm might seem like just another routine technical alert, but in reality, it is an early warning sign of an issue that could jeopardize the entire site’s performance.

Telecom engineers constantly face this challenge:

**How can RF system issues be detected before they escalate into coverage degradation or a noticeable drop in user experience?**

The challenge isn’t merely reading the VSWR value...

It lies in understanding what this value reveals about the health of the RF Path components.

When the VSWR value is high, it signifies an **impedance mismatch** between the antenna and the transmission line, causing a portion of the transmitted power to reflect back rather than being fully radiated by the antenna.

📊 **To put the issue into perspective, here are key reference values:**

* **VSWR = 1:1** $\rightarrow$ Perfect match; zero reflected power.
* **VSWR $\le$ 1.5:1** $\rightarrow$ The standard acceptable limit in telecom sites (corresponds to a Return Loss of $\ge$ 14 dB and reflected power of $\sim$4% or less).
* **VSWR > 2:1** $\rightarrow$ A threshold requiring immediate investigation, at which point some transmitters may automatically scale down output power to protect internal amplifiers.

**Common causes of high VSWR include:**

* 🔹 **Feeder Cable Degradation:** Physical damage or deterioration of the main feeder cable between the Radio Unit and the antenna.
* 🔹 **Faulty Connectors:** Improperly torqued, corroded, or loose connectors.
* 🔹 **Water Ingress:** Moisture penetrating external connectors or junction points—one of the most frequent field issues, despite often being underreported.
* 🔹 **Jumper Cable Issues:** Damaged, over-bent, or low-quality jumper cables within the installation.
* 🔹 **Impedance Mismatch Between Antenna and Transmission Line:** Discrepancies between the antenna port impedance (typically 50 $\Omega$) and the connected cable or connector impedance.

**The impact of these issues often manifests as:**

* ✅ Reduced transmission efficiency
* ✅ Coverage degradation
* ✅ Increased reflected power
* ✅ Overall site performance degradation

Therefore, resolving a VSWR alarm is not just about clearing an alert...

It is a proactive step toward maintaining network stability, reducing downtime, and ensuring an optimal user experience.

In telecommunications networks, subtle indicators often carry significant insights. An engineer who understands the relationship between VSWR, Return Loss, Reflected Power, and RF Performance can pinpoint the root cause far faster than merely treating the symptoms.

**In your experience, what is the most common cause of high VSWR in real-world deployments: water ingress, connector issues, feeder damage, or the antenna itself? And why?**